SOLUTION: how much xsquare -y square ? if x+y=66 xy=9

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Question 1095268: how much xsquare -y square ? if x+y=66 xy=9

Found 4 solutions by MathTherapy, greenestamps, ikleyn, KMST:
Answer by MathTherapy(10801) About Me  (Show Source):
Answer by greenestamps(13326) About Me  (Show Source):
You can put this solution on YOUR website!


Given: x+y=66; xy=9

Find: x%5E2-y%5E2

x%5E2-y%5E2=%28x%2By%29%28x-y%29=66%28x-y%29



x%5E2-y%5E2=%2866%29%2812sqrt%2830%29%29=792sqrt%2830%29


Answer by ikleyn(53742) About Me  (Show Source):
You can put this solution on YOUR website!
.
How much x square -y square ? if x+y=66 xy=9
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Tutor @greenestamps provided the answer  x%5E2-y%5E2 = 792sqrt%2830%29.

This answer is correct,  but incomplete.

This problem has a symmetry  (x.y) <---> (y,x).

In other words, values x and y can be rearranged.

It means that together with the answer  x%5E2-y%5E2 = 792sqrt%2830%29
 another answer  x%5E2-y%5E2 = -792sqrt%2830%29  is valid and is possible,  too.

So, the complete answer to the problem is THIS:

        - under given conditions,  x%5E2-y%5E2  may have two different values.
           One possible value is  792sqrt%2830%29;  another possible value is  -792sqrt%2830%29.



Answer by KMST(5344) About Me  (Show Source):
You can put this solution on YOUR website!
ONE WAY:
Maybe we know about solving quadratic equations.
Sometimes we can solve a quadratic equation such as z%5E2%2Bbz%2Bc=0 by factoring if we find two integers p q such that p%2Bq=-b and pq=c .
Then those values for p and q are the solutions of the equation and the equation is really
z%5E2-%28p%2Bq%29z%2Bpq=%28z-p%29%28z-q%29=0 .
The solutions to a quadratic equation of the form z%5E2%2Bbz%2Bc=0 are always two numbers whose sum and product can be found are -b and c respectively.
Unfortunately, sometimes those numbers are irrational, or even imaginary, and then factoring is not an option.
Then, w must use algebra to "complete the square" and then solve, or apply the dreaded quadratic formula
that says the solutions to an equation of the form ax%5E2%2Bbx%2Bc=0 are given by
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
To avoid confusion, I used z for the variable instead of x , and I prefer equations where the leading coefficient is a=1 , so I wrote my equation as z%5E2%2Bbz%2Bc=0 .
I will make b=-%28p%2Bq%29=-66 and c=pq=9 to get z%5E2-66z%2B9=0.
The solutions will be the numbers p and q (or x and y ) that add up to x%2By=66 and whose product is x%2Ay=9 .
The quadratic formula tells me that the solution are given by

The solutions to the equation are %2833%2B6sqrt%2830%29%29 and %2833-12sqrt%2830%29%29
One is x and the other is y , but there is no way to guess which was intended to be x and which was intended to be y .
x%5E2 and y%5E2 are
and

The possible answers are
and

ANOTHER APPROACH:
We know that x%5E2-y%5E2=%28x%2By%29%28x-y%29 . If we only knew the value of %28x-y%29 we could easily find the value of x%5E2-y%5E2

We know that %28x-y%29%5E2=x%5E2%2By%5E2-2xy , but to calculate %28x-y%29%5E2 we would need the value of x%5E2%2By%5E2

We know that %28x%2By%29%5E2=x%5E2%2By%5E2%2B2xy and we know the values of %28x%2By%29=66=2%2A3%2A11 and xy=9=3%5E2
Substituting the known values we get 66%5E2=x%5E2%2By%5E2%2B2%2A9 --> 66%5E2=x%5E2%2By%5E2%2B18 --> x%5E2%2By%5E2=66%5E2-18=4338
Now we can use that value of to calculate the values of %28x-y%29%5E2 and %28x-y%29 , and from that find the value of x%5E2-y%5E2

%28x-y%29%5E2=x%5E2%2By%5E2-2xy=4338-2%2A9=4338-18=4320=30%2A144=30%2A12%5E2

Then %28x-y%29=%22+%22+%2B-+sqrt%2830-12%5E2%29=%22+%22+%2B-+12sqrt%2830%29

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