SOLUTION: Please explain how to solve Sqrt 5x+1-4 = 0. I get the following; sqrt 5x+1-4=0 sqrt 5x-3=0 5x-3=0^2 5x-3=0 5x-3+3=0+3 5x=3 5x/5 = 3/5 x=3/5 Thank you.

Algebra ->  Radicals -> SOLUTION: Please explain how to solve Sqrt 5x+1-4 = 0. I get the following; sqrt 5x+1-4=0 sqrt 5x-3=0 5x-3=0^2 5x-3=0 5x-3+3=0+3 5x=3 5x/5 = 3/5 x=3/5 Thank you.      Log On


   

Question 1069137: Please explain how to solve
Sqrt 5x+1-4 = 0.
I get the following;
sqrt 5x+1-4=0
sqrt 5x-3=0
5x-3=0^2
5x-3=0
5x-3+3=0+3
5x=3
5x/5 = 3/5
x=3/5
Thank you.
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
First thing is to write it correctly, in an understandable format.

For it, use PARENTHESES.

Otherwise nobody understand how far your square root does extend.



Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Please explain how to solve
Sqrt 5x+1-4 = 0.
I get the following;
sqrt 5x+1-4=0
sqrt 5x-3=0
5x-3=0^2
5x-3=0
5x-3+3=0+3
5x=3
5x/5 = 3/5
x=3/5
Thank you.
No-one can unless you can state whether it's: matrix%281%2C3%2C+sqrt%285x+%2B+1%29+-+4+=+0%2C+or%2C+sqrt%285x+%2B+1+-+4%29+=+0%29. 

I kind of doubt it's: sqrt%285x%29+%2B+1+-+4+=+0