SOLUTION: 1.How many x-intercepts does the graph of the function have? List them out. f(x)=-(x^2+1)(x-4) 2.How many complex zeros are there to the function? List them out. f(x)=(

Algebra ->  Radicals -> SOLUTION: 1.How many x-intercepts does the graph of the function have? List them out. f(x)=-(x^2+1)(x-4) 2.How many complex zeros are there to the function? List them out. f(x)=(      Log On


   

Question 1059401: 1.How many x-intercepts does the graph of the function have?
List them out.
f(x)=-(x^2+1)(x-4)
2.How many complex zeros are there to the function?
List them out.
f(x)=(2x-1)(x^2+7)




Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1. One real root, x=4, the other roots are complex.
.
.
2. One real root,
2x-1=0
2x=1
x=1%2F2
The other roots are complex and there are two of them,
x%5E2%2B7=0
x%5E2=-7
x%5E2=7%28-1%29
x=0+%2B-+sqrt%287%29i