SOLUTION: Factor by pulling out the Greatest Common Factor 24x^4y^3-16x^3y^5
Algebra
->
Radicals
-> SOLUTION: Factor by pulling out the Greatest Common Factor 24x^4y^3-16x^3y^5
Log On
Algebra: Radicals -- complicated equations involving roots
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Radicals
Question 1054914
:
Factor by pulling out the Greatest Common Factor
24x^4y^3-16x^3y^5
Answer by
Theo(13342)
(
Show Source
):
You can
put this solution on YOUR website!
your expression is:
24x^4y^3-16x^3y^5
you've got x^4 in the first term and x^3 in the second term.
the greatest common factor that can be removed would be x^3.
you've got y^3 in the first term and y^5 in the second term.
the greatest common factor that can be removed would be y^3.
you've got 24 in the first term and 16 in the second term.
the greatest common factor that can be removed would be 8.
your final expression should be 8x^3y^3 * (3x - 2y^2)
if you multiply those factors out, you will get back to the original expression.
8x^3 * y^3 * 3x is equal to 24 * x^4 * y^3 which is the same as 24x^4y^3
8x^3 * y^3 * -2y^2 is equal to -16 * x^3 * y^5 which is the same as -16y^3y^5.
add them together and you get 24x^4y^3 - 16y^3y^5 which is the same as your original expression.
here's the original expression for convenience of comparison.
24x^4y^3-16x^3y^5