SOLUTION: Factor by pulling out the Greatest Common Factor 24x^4y^3-16x^3y^5

Algebra ->  Radicals -> SOLUTION: Factor by pulling out the Greatest Common Factor 24x^4y^3-16x^3y^5      Log On


   



Question 1054914: Factor by pulling out the Greatest Common Factor
24x^4y^3-16x^3y^5

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
your expression is:

24x^4y^3-16x^3y^5

you've got x^4 in the first term and x^3 in the second term.
the greatest common factor that can be removed would be x^3.

you've got y^3 in the first term and y^5 in the second term.
the greatest common factor that can be removed would be y^3.

you've got 24 in the first term and 16 in the second term.
the greatest common factor that can be removed would be 8.

your final expression should be 8x^3y^3 * (3x - 2y^2)

if you multiply those factors out, you will get back to the original expression.

8x^3 * y^3 * 3x is equal to 24 * x^4 * y^3 which is the same as 24x^4y^3

8x^3 * y^3 * -2y^2 is equal to -16 * x^3 * y^5 which is the same as -16y^3y^5.

add them together and you get 24x^4y^3 - 16y^3y^5 which is the same as your original expression.

here's the original expression for convenience of comparison.

24x^4y^3-16x^3y^5