You can put this solution on YOUR website! √(2x+1)+√(x-3)=2
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Square both sides to get:
(2x+1)+(x-3) + 2*sqrt[(2x+1)(x-3)] = 4
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sqrt[2x^2 -5x -3] = -3x+6
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Square both sides again to get:
2x^2-5x-3 = 9x^2 -36x + 36
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7x^2 -31x + 39 = 0
b^2-4ac < 0
So, no Real Number solution.
Cheers,
Stan H.
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