Question 1032410: The expression sqrt(729g^5y^3)^3 (729g^5y^3) equals kg^ry^s
where r, the exponent of g, is:
And s, the exponent of y is:
And k, the leading coefficient is:
The exponent raised to the 3 on the first squate root is supposed to be a cube(third) root
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The expression sqrt(729g^5y^(1/3))^3 (729g^5y^3) equals kg^ry^s
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= 729^(3/2)*g^(15/2)*(y))(729*g^5*y^3) = k*g^r*y^s
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= 729^(5/2)*g^(25/2)*y^(6)
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where r, the exponent of g, is: r = 0
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And s, the exponent of y is: 1+3 = 4
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And k, the leading coefficient is: (3/2)+1 = 5/2
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The exponent raised to the 3 on the first squate root is supposed to be a cube(third) root
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Cheers,
Stan H.
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