SOLUTION: (16n^1/3/n)^-1/4+2n^1/6-n1/3 (Image it is confusing http://i.imgur.com/EOXiNTF.png)
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Algebra: Radicals -- complicated equations involving roots
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Question 1024428
:
(16n^1/3/n)^-1/4+2n^1/6-n1/3 (Image it is confusing http://i.imgur.com/EOXiNTF.png)
Found 2 solutions by
Fombitz, Theo
:
Answer by
Fombitz(32388)
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You can
put this solution on YOUR website!
It's very confusing, you didn't use enough parentheses (they're free).
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Answer by
Theo(13342)
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):
You can
put this solution on YOUR website!
see the following worksheets:
the graph of the original equation is shown below.
the equation is formed by setting the expression equal to y.
the variable of x was used in place of n for graphing purposes.
step 1 is the original equation.
step 2 simplifies it by utilizing the fact that (a*(b^c)/d)^e is equal to a^e * (b^c)^e / d^e.
step 3 simplifies it further by utilizing the fact that a^-b = 1/a^b and (a^b)^-c = 1/(a^b)^c.
step 4 simplifies it further by utilizing the fact that (a^b)^c = a^(b*c).
step 5 simplifies it further by utilizing that fact that (a^b)/a^c) = a^(b-c).
step 6 simplifies it further by performing the operation indicated in step 5.
step 7 turns the expression into an equation by setting it equal to 0.
step 8 multiplies both sides of the equation by 2.
step 9 combines like terms.
step 10 utilizes the fact that n^(1/3) is equivalent to (n^1/6)^2.
step 11 factors out the common term of n^(1/6).
step 12 sets the first factor equal to 0 and solves for n to get n = 0.
step 14 sets the second factor equal to 0 and solves for n to get n = 244.140625.
the graph of the original equation confirms the solution is correct.