SOLUTION: Solve sqrt(b+1)=sqrt(b+6) -1

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Question 1018441: Solve
sqrt(b+1)=sqrt(b+6) -1
Found 2 solutions by Boreal, addingup:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(b+1)=sqrt(b+6) -1;
square both sides
b+1=b+6-2sqrt(b+6)+1
collect terms
-6=-2 sqrt(b+6)
3=sqrt (b+6)
square
9=b+6
b=3
-------
must check to be sure this works
sqrt(4)=sqrt(9)-1
2=3-1.
It does.

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for b:
sqrt%28b%2B1%29+=+sqrt%28b%2B6%29-1
Get rid of the square root on the left, raise both sides to the power of two:
(((b+1 = (sqrt(b+6)-1)^2}}}
Subtract %28sqrt%28b%2B6%29-1%29%5E2 from both sides in order to move everything to the left side:
1%2Bb-%28sqrt%28b%2B6%29-1%29%5E2+=+0
Expand the terms on the left and you get:

Divide both sides by 2:
sqrt%28b%2B6%29+=+3
Raise both sides to the power of two to get rid of the square root:
b+6 = 9
Subtract 6 from both sides:
b = 3
Happy learning,
J