SOLUTION: {{{(7-5x)^1/2 >or= 8}}}

Algebra ->  Radicals -> SOLUTION: {{{(7-5x)^1/2 >or= 8}}}      Log On


   

Question 1016072: %287-5x%29%5E1%2F2+%3Eor=+8
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
Is this supposed to be: %287-5x%29%5E1%2F2+%3E=+8 -OR- %287-5x%29%5E%281%2F2%29+%3E=+8 . (exponent=1/2)
.
%287-5x%29%5E1%2F2+%3E=+8 . Multiply each side by 2.
7-5x%3E=16 . Subtract 7 from each side.
-5x%3E=9 . Divide each side by -5. . (reverse inequality)
x%3C=-%289%2F5%29
.
-OR-
.
%287-5x%29%5E%281%2F2%29+%3E=+8 . Exponent is 1/2.
sqrt%287-5x%29%3E=8 . Square both sides.
7-5x%3E=64 . Subtract 7 from each side.
-5x%3E=57 . Divide each side by -5. . (reverse inequality)
x%3C=-%2857%2F5%29
.