SOLUTION: (z+4)^(4/5)=2 Where z is a real number.

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Question 1013852: (z+4)^(4/5)=2 Where z is a real number.
Found 3 solutions by Alan3354, Edwin McCravy, AnlytcPhil:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(z+4)^(4/5)=2
(z+4)^4 = 32
z%2B4+=+root%284%2C32%29+=+2root%284%2C2%29
z+=+-4+%2B+2root%284%2C2%29

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
There are two solutions. The other tutor did not get both solutions.
I'll go into a little more detail.



Raise both sides of the equation to the reciprocal of 4%2F5
power, which is the 5%2F4 power:



Remove the parentheses on the left by multiplying the exponents 
which just gives the exponent 1.

On the right we use the rule: 

But since the root we are taking is even, the fourth root,
there are two fourth roots, positive and negative, so we must
precede it by ±:












So there are two solutions, 

 and 

Edwin








Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
Another way to get both solutions is this:



Raise both sides to the 5th power



Multiply exponents

matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C%0D%0A%28z%2B4%29%5E4%2C%22%22=%22%22%2C32%29

Use the principle of even roots (fourth root):









That way you get both solutions.

Edwin