SOLUTION: Solve: y-1 = sqrt 2y-2
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Question 1008299
:
Solve:
y-1 = sqrt 2y-2
Answer by
stanbon(75887)
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y-1 = sqrt (2y-2)
----
(y-1)^2 = 2y-2
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y^2 -2y + 1 = 2y - 2
----
y^2 - 4y + 3 = 0
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Factor::
(y-1)(y-3) = 0
----
y = 1 or y = 3
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Cheers,
Stan H.
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