SOLUTION: 1. Which equation has more than one real-number solution?
a. x2 = 0
b. x2 = 1
c. x2 = –1
d. x3 = –1
Would it be C? Because you would square root -1, so it would become
Algebra ->
Radicals
-> SOLUTION: 1. Which equation has more than one real-number solution?
a. x2 = 0
b. x2 = 1
c. x2 = –1
d. x3 = –1
Would it be C? Because you would square root -1, so it would become
Log On
Question 1003382: 1. Which equation has more than one real-number solution?
a. x2 = 0
b. x2 = 1
c. x2 = –1
d. x3 = –1
Would it be C? Because you would square root -1, so it would become +/- √1? Answer by mananth(16946) (Show Source):