SOLUTION: 1. Which equation has more than one real-number solution? a. x2 = 0 b. x2 = 1 c. x2 = –1 d. x3 = –1 Would it be C? Because you would square root -1, so it would become

Algebra ->  Radicals -> SOLUTION: 1. Which equation has more than one real-number solution? a. x2 = 0 b. x2 = 1 c. x2 = –1 d. x3 = –1 Would it be C? Because you would square root -1, so it would become      Log On


   



Question 1003382: 1. Which equation has more than one real-number solution?
a. x2 = 0
b. x2 = 1
c. x2 = –1
d. x3 = –1
Would it be C? Because you would square root -1, so it would become +/- √1?

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%281%29 = +/- 1
so b