Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 1043507: A tunnel has the shape of a semi-ellipse that is 15 ft. high at the center and 36 ft. across at the base. At most how high should a passing truck be, if it is 12 ft. wide for it to be able to fit to the tunnel? Round off your answer to two decimal places.
Click here to see answer by josgarithmetic(39618)  |
Question 1043488: A cable wire was tied to both ends of a 240 meters long bridge such that the cable hangs in the form of a parabola. The lowest point of the cable is 60 meters below the bridge.
a.) Find the equation of the cable wire, assuming that the origin is the lowest point of the cable.
b.) Using the equation, find the width of the rope at a point 38 meters above its lowest point.
c.) suppose a 180 neters rope will be tied horizontally to the cable wire. How high above the lower point of the cable wire should the rope be?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 1044355: Write the equation of the ellipse in standard form that satisfies the given conditions. Draw the ellipse, its focus, and directrix.
1.) The center is at (2,4), a vertex is at (-11,4), and the length of the minor axis is 24.
*Please help me solve this :( It would really mean so much to me. I badly need help in Math.
Click here to see answer by MathLover1(20850)  |
Question 1045059: Acceleration of Gravity and Newton's Second Law
Newton's Second Law
"Change of motion is proportional to the force applied, and take place along the straight line the force acts."
Velocity and Distance Traveled by a Free Falling Object
The velocity after some time for a free falling object can be expressed as:
v = g t ------(1)
where
v = velocity (m/s)
The distance traveled after some time by a free falling object can be expressed as:
Why we are using HEIGHT=1/2 G(T^2)-----(2)
Here,
HEIGHT represents the height at which the object is falling.
G represents the gravitational force=9.8m/s^2
T represents the time taken for the object to fall.
My doubt is why we are using 1/2 in the equation--(2),why cant we use 1/4,3/4 or 1
Click here to see answer by ikleyn(52795)  |
Question 1045127: A parabola of the form y=ax^2+bx+c has a maximum value of y=3. The y-coordinate of the parabola at x=5 is (9/4). The y-coordinate of the parabola at x=7 is (-15/4). Determine the x-intercepts of the parabola. Enter your answer in exact form.
Use this form of the equation of a parabola:
y=a(x-h)^2+k
Then h is the x-coordinate of the maximum and k is the maximum value. You'll then need to sub in the two data points to get two equations, which you can solve for a and h or k. Once you've done this you'll have the equation of your parabola, so you can set y = 0 and solve for the x-intercepts.
You'll need to know that the max of a downward facing parabola (negative a) is at the vertex. The vertex has x-coordinate :
xV=(-b/2a)
Smaller X-intercept:
Larger X-intercept:
Click here to see answer by josgarithmetic(39618) |
Question 1045398: Write the equation of the ellipse in standard form that satisfies the given conditions. Draw the ellipse, its focus, and directrix.
*The center is at (3,4), a focus is at (3,-1), and the length of the major axis is 26.
--Please help :( Thank you so much.
Click here to see answer by ikleyn(52795) |
Question 1045388: The arch of a bridge is in the shape of a semiellipse, with its major axis at the water level. Suppose the arch is 20 ft. high in the middle, 120 ft. across its major axis. How high above the water level is the arch, at point 20 ft. from the center (horizontally). Round off to 2 decimal places.
Click here to see answer by KMST(5328)  |
Question 1045393: Write the equation of the ellipse in standard form that satisfies the given conditions. Draw the ellipse, its focus, and directrix.
2.) The vertices are at (3,-3) and (3,5) and the length of the minor axis is 6.
Please help me with my homework :'( Thank you so much. It would really sooooo much to me and would be greatly appreciated ^_^
Click here to see answer by ewatrrr(24785)  |
Question 1045442: The orbit of a planet around a star is described by the equation (x^2/640,000)+(y^2/630,000) = 1 , wherein star is at one focus, and all units are in millions of kilometers. The planet is closest and farthest from the star, when it is at the vertices. How far is the planet when it is farthest from the star?
Click here to see answer by MathLover1(20850) |
Question 1045391: Write the equation of the ellipse in standard form that satisfies the given conditions. Draw the ellipse, its focus, and directrix.
1.) The center is at (-2,4). a vertex is at (3,4), and a focus is at (4,4).
Your help would be so much appreciated and of great help. Thank you so much :)
Click here to see answer by stanbon(75887) |
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