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Question 1041495: Sketch the following questions. Involving parabola..
A satellite dish has a shape called a paraboloid,where each cross-section is a parabola. Since radio signals (parallel to the axis) will bounce off the surface of the dish to the focus, the receiver should be placed at the focus. How far should a receiver be from the vertex, if the dish is 12 ft. across 4.5 ft. deep at the vertex?
Click here to see answer by josgarithmetic(39620) |
Question 1041774: A flashlight is shaped like a paraboloid and the light source is placed at the focus so that the light bounces off parallel to axis of symmetry; this is done to minimize illumination. A particular flashlight has its light source located 1 cm. from the base and is 6 cm. deep. What is the width of the flashlight's opening?
Click here to see answer by josgarithmetic(39620) |
Question 1042006: I have an algebra 2 question that is about finding an polynomial function that will create three "hills" on a graph. These hills can't be crazy numbers and have to be in the first quadrant. The X-axis is the ground. I asked my teacher and she said that I should compress x^6 and it should work out. However, whenever I graph x^6, it always ends up being a parabola. How can I find the correct equation? Thank you so much for the time and effort :)
Click here to see answer by josgarithmetic(39620) |
Question 1042105: a satellite dish has a shape called paraboloid where each cross section is a parabola since ratio signals (parallel to the x-axis will bounce off the surface of the dish to the focus the receiver should be placed at the focus.How far should the receiver be from the vertex if the dish is 12 ft across and 4.5 ft deep at the vertex?
Click here to see answer by josgarithmetic(39620) |
Question 1042427: A parkway 20 meters wide is spanned by a parabolic arc 30 meters long along the horizontal. If the parkway is centered, how high must the vertex of the arch be in order to give a minimum clearance of 5 meters over the parkway. (Solve using the equation of parabola)
Click here to see answer by rothauserc(4718)  |
Question 1042585: Hey, can someone please help?
Solve by completing the square: 9x=5x^2-1
I can normally figure out complete the square problems, but the leading coefficient in this is throwing me off! Please help! thank you!
Click here to see answer by Boreal(15235)  |
Question 1042719: The towers supporting the cable of suspension bridge are 1200m apart and 170m above the bridge it supports.Suppose the cable hangs,following the shape of parabola,with its lowest point 20m above the bridge.How high is the cable 120m away from a tower? Sketch the graph.
Click here to see answer by ankor@dixie-net.com(22740)  |
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