Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 852319: Find an equation for the hyperbola with foci (−3,−1) and (−3, 9) and asymptotes y = −3x/4 25/4 y = 3x/4 + 25/4 . Write your answer in the form (y-d)^2/a^2 -(x-c)^2/b^2 =1.
Not sure on how to approach this.
Click here to see answer by ewatrrr(24785)  |
Question 852529: Kurt says that you can take the square root of each side of an equation. Therefore, he says (x+2)^2+(y-5)^2=36 and (x+2)+(y-5)=6 are equivalent equations. Dana says they are NOT. Who is correct? Explain your answer?
Click here to see answer by Alan3354(69443)  |
Question 853690: The directions for the question is "Write an equation for the circle that satisfies each set of conditions."
But the actual question is, "center (8,-9), passes through (21,22)." I have no clue what to do or where to start please help...
Click here to see answer by josgarithmetic(39618) |
Question 853710: The question was "An open box with a square base is to be made from a square piece of cardboard 30in. on a side by cutting out a square from each corner and turning up the sides. Express the V of the box as a function of the length x of the side of the square cut from each corner." Now I already know the function is V=x(30-2x)(30-2x) but the next question goes on to ask what is the volume if 6 in. sq. is cut out? Would you just plug 6 in for x??? And also it goes on to another one of these questions asking if 14 in. sq. is cut out what is the volume? Any help would be much appreciated! Thanks!
Click here to see answer by josgarithmetic(39618) |
Question 853710: The question was "An open box with a square base is to be made from a square piece of cardboard 30in. on a side by cutting out a square from each corner and turning up the sides. Express the V of the box as a function of the length x of the side of the square cut from each corner." Now I already know the function is V=x(30-2x)(30-2x) but the next question goes on to ask what is the volume if 6 in. sq. is cut out? Would you just plug 6 in for x??? And also it goes on to another one of these questions asking if 14 in. sq. is cut out what is the volume? Any help would be much appreciated! Thanks!
Click here to see answer by josmiceli(19441)  |
Question 854090: Currently, we are working on horizontal parabolas. I am supposed to find the vertex, focus, and directrix of this formula:
I've been working the equation, and my work currently looks like this:

I don't know what to do with the 23/4. Any help would be appreciated :) Thank you!
Click here to see answer by lwsshak3(11628) |
Question 855099: A bridge is built in the shape of a semielliptical arch. The bridge has a span of 120 feet and a maximum
height of 25 feet. Choose a suitable rectangular coordinate system and find the height of the arch at distances of
10, 30, and 50 feet from the center.
Click here to see answer by lwsshak3(11628) |
Question 855252: Graph the relation defined by the inequality (y^2/4) - (x^2/25)>1. On your graph, indicate the vertices and the foci and draw the asymptotes as dotted lines. Express the domain and the range of this relation in set-builder notation.
Click here to see answer by ewatrrr(24785)  |
Question 855915: write the equation of the parabola with vertex at the origin which satisfies the given condition:
a.axis on the y-axis and passes through (6,-3)
b.focus (0,4/3) and the equation of the directrix is y+4/3=0
c.directrix is x-4=0
d.focus at(0,2)
e. latus rectum is 6 units and the parabola opens to the left
f.focus on the x-axis and passes through (4,3)
ive tried answering but i dont know if i got the ryt answers . can anybody help me ? thank u so much in advance god bless
Click here to see answer by KMST(5328)  |
Question 856050: The parabolic arch in the concrete bridge in
the figure must have a clearance of 50 feet above the water
and span a distance of 200 feet. Find the equation of the
parabola after inserting a coordinate system with the origin
at the vertex of the parabola and the verticaly axis (point-ing upward) along the axis of the parabola.
Click here to see answer by ankor@dixie-net.com(22740)  |
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