Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 711281: write an equation of the conic section
parabola with vertex at (2,6) and directrix at y=8
use the discriminant to classify the conic section
9y^2-x^2+2x+54y+62=0
classify the conic section and write its equation in standard form. then graph the equation
x^2+y^2+10x-12y+40=0
Click here to see answer by lwsshak3(11628) |
Question 711965: find a polynomial equation with integer coefficients for the set of coplanar points described;
each point is twice as far from the line x=3 as it is from the line y =-2
also;
is the graph a conic section, if so what section?
Click here to see answer by stanbon(75887) |
Question 711964: If it is a parabola, give it's vertex, focus, and directrix; if it is an ellipse, give it's center, vertices, and foci; if it's a hyperbola, give it's center, vertices, foci, and asymptotes
The problem: x^2 + 4y = 4
Click here to see answer by lwsshak3(11628) |
Question 711274: A bridge is built in the shape of a semielliptical arch. The bridge has a span of 60 feet and a maximum height of 20 feet. Find the height of the arch at distances 5, 10, and 20 feet from the center.
The answers are in the back of my textbook, but I have no idea how to get to the answer.
I started with finding the points on the arch (0,20) with, I'm assuming, the vertices (-30,0) and (30,0) when I drew it out.
Click here to see answer by lwsshak3(11628) |
Question 712593: A hyperbolic mirror can be used to take panoramic photos, if the camera is pointed toward the mirror with the lens at one focus of the hyperbola. write the equation of the hyperbola that can be used to model a mirror that has a vertex 4 inches from the center of the hyperbola and a focus 1 inch in front of the surface of the mirror. assume the mirror has a horizontal trasverse axis and the hyperbola is centered at (0,0).
Click here to see answer by lwsshak3(11628) |
Question 714369: Hello, i need some guidance on this hyperbola problem. On my test, it says to find the vertices, center and the foci of y^2 over 5, minus x^2 over 11=1. Or, if this is another way to write out my problem-> y^2/5-x^2/11=1. Thank you
Click here to see answer by lwsshak3(11628) |
Question 715317: I basically have a general question. I am trying to use information provided to write the transformational equation of each parabola. I am given the vertex and focus and the vertex and directrix. I know how to find p but I do not where to put it and when the x is squared vs the y being squared. I guess I need the rules?
Example: Vertex: (-7,-8) Focus: (47/8,8)
Knowing that the Vertex is (h,k)...
I take the absolute value of 6-(47/8)=(1/8)... (1/8) is the value of p
4*(1/8)= .5
After that I am lost...
Click here to see answer by stanbon(75887) |
Question 716150: Given the equation (x+3)^2/36+(y-1)^2/18=1
find: the center. I found (-3,1)
vertices (-3.-5) and (-3,7)
the end points of minor axis I only came up with 6 radical 2
the foci I got 3 radical 2 and length of major axis is 12
Are these correct?
I can't find the length of focal cord or its endpoints.
Please help
Click here to see answer by solver91311(24713)  |
Question 716641: Please help me solve this equation: 
a.Write the equation in standard form.
b.Find the coordinates of the vertex and focus,direction of opening, the equations for the directrix and the axis of symmetry,and latus rectum
c.Graph the equation of the parabola
Click here to see answer by lwsshak3(11628) |
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