Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 387953: I am trying to find the y-intercept, as an ordered pair, of the equation . I have tried solving it myself by making "x" equal to 0 and then I simplified the equation to , and I was unsure as to what to do after that, or if that was even right. Thank you, and if there was any way that you could show me the steps you took that would be great. Thanks again.
Click here to see answer by nerdybill(7384)  |
Question 387953: I am trying to find the y-intercept, as an ordered pair, of the equation . I have tried solving it myself by making "x" equal to 0 and then I simplified the equation to , and I was unsure as to what to do after that, or if that was even right. Thank you, and if there was any way that you could show me the steps you took that would be great. Thanks again.
Click here to see answer by 533908(1) |
Question 388476: Graph the parabola:
Y=(x+1)^2-1
To graph the parabola, plot the vertex and four additional points, two on each side of the vertex, and then click on the graph icon.
It says I need 5 Points
I have the vertex as (-1,-1)
and two other points of (-2,0) and (0,0) I can't figure the other two points any help would be greatly appreciated.
Click here to see answer by nerdybill(7384)  |
Question 389516: It asks for the standard form of the equation of this conic:
4x^2 - 5y^2 - 16x - 30y - 9 = 0
I know the standard form is going to be the form of a hyperbola, since a and c are not equal and have opposite signs.
I also know that completing the square is part of solving this too, I just don't really know how to apply it to a conic.
Help is much appreciated!
Click here to see answer by haileytucki(390)  |
Question 389514: An isosceles triangle with base 6 cm and base angles 30 degrees each is inscribed in a circle. A second circle,which is situated outside the triangle, touches the first circle and also touches the base of the triangle at its midpoint. Find its radius.
Click here to see answer by lwsshak3(11628) |
Question 390072: A ball is tossed into the air at an initial velocity of 38.4ft/sec from .96 feet off of the ground.
At what point does the ball hit the ground?
I figured out that the equation is y=-16t^2+38.4t+.96
I also figured out that the maximum height of the ball is 24 feet and it reaches it's maximum in 1.2 seconds.
Click here to see answer by stanbon(75887) |
Question 390072: A ball is tossed into the air at an initial velocity of 38.4ft/sec from .96 feet off of the ground.
At what point does the ball hit the ground?
I figured out that the equation is y=-16t^2+38.4t+.96
I also figured out that the maximum height of the ball is 24 feet and it reaches it's maximum in 1.2 seconds.
Click here to see answer by nerdybill(7384)  |
Question 390339: A road is 32 feet wide is 0.4 foot higher in the center then it is on its sides.
a) Find the equation of the parabola (Assume that the origin is at the center of the road) - Show all work
b) How far from the center of the road is the road surface 0.1 foot lower than in the middle? -show all work.
please show work and thank you.
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 390535: One Minor axis vertex is located at (2,-2).Find the other minor axis vertex for the ellipse defined by the equation. (x-1)^2/1 + (y+2)^2/49 =1. I know that the center is (1,-2) and A^2= 49 A=7 but I don't know what to do after that to solve this problem. please help.
Click here to see answer by ewatrrr(24785)  |
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