Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 381315: This is the exact question asked:
Give an equation of the parabola which opens either up or down given the three points of: (0,11), (1,21), and (-2,3) on the parabola.
I just don't know how to do this! Thanks so much and God bless you.
-Zach
Click here to see answer by stanbon(75887) |
Question 381342: Question reads:
"Complete the square on the hyperbola: x^2-4y^2+2x+8y-19=0. Finally, draw a quick sketch. A sketch from a graphics calculator is acceptable."
Don't know to complete the square or what to punch in on "y=" on my graphing calculator! Thanks a bunch!
Zach
Click here to see answer by stanbon(75887) |
Question 381502: what does any of this hav to do with everyday life i dont think ill ever have to find the vortex of a parabola will im shoping at the groccery store man i dont think its fair that we have to have these extremely hard classes to graduate.......
Click here to see answer by stanbon(75887) |
Question 381887: Why is the vertex of a parabola important to us? Specifically, what kind of information does the vertex give us? In your explanation include a real-world example where a quadratic model is appropriate, identify the vertex, and explain what the vertex represents. (TEXTBOOK)
Click here to see answer by richard1234(7193)  |
Question 383377: I apologize if the incorrect topic is chosen from the drop down menu, it is about a quarter inch wide.
I cannot find information in my book to solve this particular iteration of a graph of a hyperbola. The furthest I can get is finding the center. The problem is (y+6)^2 - (x-2)^2=1. The center is (2,-6). All other problems in the book look different, and I did not purchase the solution manual. I have tried several things, but I am getting nothing but frustrated. Please help?
Click here to see answer by Fombitz(32388)  |
Question 383818: Directions: For each of the following conic sections identify whether it is a circle, parabola, ellipse or hyperbola. Find its center and/or vertices, its focus or foci, major or transverse axis, if appropriate, asymptotes or directrix if present. Graph each of them, labeling all important points.
The question I'm having trouble with is:
4x^2+y^2-24x+4y+36=0
So far, I've gotten this, but I think I did something wrong:
4x^2+y^2-24x+4y+36=0
[-4(x+3)^2-9]+y^2+4y+36=0
[-4(x+3)^2-9]+(y+2)^2-4+36=0
[-4(x+3)^2]+(y+2)^2=-68
*divide by -68*
[((x+3)^2)/7] + [((y+2)^2)/-68]=1
I think it's an ellipse, but I'm not sure. The -68 is really throwing me off.
Click here to see answer by solver91311(24713)  |
Question 385192: Convert 2x^2 + 2y^2 + 6x - 8y + 12 = 0 into center-radius form.
I divided by 2 to get a coefficeint of one. then when I tried to complete the square I didn't know what to do with the 3.
x^2 + 3x + ___ + y^2 + 4y + 2 = -6 + ____ + 2
Click here to see answer by Fombitz(32388)  |
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