SOLUTION: for the parabola : y = -x^2 + 36. Graph of a parabola opening down at the vertex (0,36) crossing the x–axis at (-6,0) and (6,0).

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: for the parabola : y = -x^2 + 36. Graph of a parabola opening down at the vertex (0,36) crossing the x–axis at (-6,0) and (6,0).      Log On


   

Question 993785: for the parabola : y = -x^2 + 36.
Graph of a parabola opening down at the vertex (0,36) crossing the x–axis at (-6,0) and (6,0).
Answer by solver91311(24713) About Me  (Show Source):
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John

My calculator said it, I believe it, that settles it