SOLUTION: find the center and raidus of this equation (x-5)^2+(y+4)^2=24

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Question 973819: find the center and raidus of this equation
(x-5)^2+(y+4)^2=24
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
find the center and raidus of this equation
(x-5)^2+(y+4)^2=24
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Center: (5,-4)
r+=+sqrt%2824%29
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That's the center and radius of the circle defined by the equation.
Equations don't have centers or radii.