SOLUTION: I have an equation of a semi-ellipse that I found from the graph. I need to get it into y= form from standard form. The equation right from the graph is ((x-10)^2)/64 + (y^2)/256 =
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-> SOLUTION: I have an equation of a semi-ellipse that I found from the graph. I need to get it into y= form from standard form. The equation right from the graph is ((x-10)^2)/64 + (y^2)/256 =
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Question 972711: I have an equation of a semi-ellipse that I found from the graph. I need to get it into y= form from standard form. The equation right from the graph is ((x-10)^2)/64 + (y^2)/256 = 1
If possible, please show work as well. Thank you very much! Found 2 solutions by stanbon, Boreal:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I have an equation of a semi-ellipse that I found from the graph. I need to get it into y= form from standard form. The equation right from the graph is
((x-10)^2)/64 + (y^2)/256 = 1
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Get rid of the denominators
256(x^2-10) + 64y^2 = 64*256
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64y^2 = -256(x^2-10) + 64*256
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y = +-[4*(x^2-10) + 256]
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y = +-[4x^2+216]
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Cheers,
Stan H.
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You can put this solution on YOUR website! Start by moving the x to the other side
[y^2/256]= 1- [(x-10)^2/64] Now multiply by 256 and then take the square root.
Y^2= 256-4(x-10)^2
Y=+/- sqrt [256-4(x-10)^2] I will call this (1); Notice that it is a difference of squares.
= sqrt {(16+2(x-10)) (16-(2(x-10))} sqrt{ (2x-4) (-2x+36)} I will call this (2)
I graphed (1) below, but (2) graphs the same on a TI-83.
(