SOLUTION: x^2-5y+20=0

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Question 971660: x^2-5y+20=0
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
I will edit this problem to be x^2-5x+20=0, since that can be graphed and roots may be found. The equation as written can only be substituted for y or for x.
Large positive constant suggests complex roots
quadratic formula x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29
x= (1/2) {5 +/- sqrt (25-80)} sqrt = -55 = i sqrt(55)
x= (1/2) * (5 +/- i sqrt (55) ) Graph will show no crossing of x-axix, parabola, with vertex at x=(5/2)
+graph+%28300%2C200%2C-10%2C10%2C-10%2C50%2Cx%5E2-5x%2B20%29