SOLUTION: How do you get the answer (x-4)^2/49 + (y+8)^2/81 = 1 when the center is (4,-8)and the height is 18 and width is 14?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How do you get the answer (x-4)^2/49 + (y+8)^2/81 = 1 when the center is (4,-8)and the height is 18 and width is 14?      Log On


   

Question 959438: How do you get the answer (x-4)^2/49 + (y+8)^2/81 = 1 when the center is (4,-8)and the height is 18 and width is 14?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do you get the answer (x-4)^2/49 + (y+8)^2/81 = 1 when the center is (4,-8)and the height is 18 and width is 14?
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This is an equation of an ellipse with vertical major axis
Its standard form of equation: %28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, a>b, (h,k)=coordinates of center
Given equation: %28x-4%29%5E2%2F49%2B%28y%2B8%29%5E2%2F81=1
Given height of 18=length of vertical major axis=2a
a=9
a^2=81
..
Given width of 14=length of minor axis=2b
b=7
b^2=49
..
given center of (4,-8) is seen in given equation of ellipse