SOLUTION: 2x2−4y2−20x−16y+26=0 | Find the Standard Form of the Hyperbola Answer

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Question 955850: 2x2−4y2−20x−16y+26=0
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Find the Standard Form of the Hyperbola
Answer


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2x2−4y2−20x−16y+26=0
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Find the Standard Form of the Hyperbola
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2x^2 - 20x -4y^2 - 16y = -26
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2(x^2-10x) - 4(y^2+4y) = -26
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Complete the square::
2(x^2-10x+25) -4(y^2+4y+4) = -26 + 2*25 - 4*4
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2(x-5)^2 -4(y+2)^2 = 8
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(x-5)^2/4 - (y+2)^2/2 = 1
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Cheers,
Stan H.
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