SOLUTION: i don't know what the heck they are talking about.... really. For all numbers x and y, that let x triangle y be defined as x triangle y = x squared + xy + y squared. What is the

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: i don't know what the heck they are talking about.... really. For all numbers x and y, that let x triangle y be defined as x triangle y = x squared + xy + y squared. What is the      Log On


   



Question 9356: i don't know what the heck they are talking about.... really.
For all numbers x and y, that let x triangle y be defined as x triangle y = x squared + xy + y squared. What is the value of: (3 triangle 1) triangle 1?
what the f'ck!?!?!?!

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
lol it is just an exercise in semantics to be honest...

ok, let x triangle y = x%5E2+%2B+xy+%2B+y%5E2. I shall write this as follows, for ease of writing:

xTy = x%5E2+%2B+xy+%2B+y%5E2

so... when you see 2T5 for example, you look at the definition, which says xTy ie x=2 and y=5 and you put these values into the equation as stated, namely the x%5E2+%2B+xy+%2B+y%5E2

so, to your question... What is the value of: (3 triangle 1) triangle 1? Well, we have brackets, so we have to do the thing inside the bracket first...so

3T1 means x=3, y=1 in x%5E2+%2B+xy+%2B+y%5E2, giving %283%29%5E2+%2B+%283%29%281%29+%2B+%281%29%5E2 which is 9 + 3 + 1 --> 13.

And now, from (3T1)T1 we have 13T1, where x=13 and y=1, so %2813%29%5E2+%2B+%2813%29%281%29+%2B+%281%29%5E2 which is 169 + 13 + 1 which gives 183.

Hope it isn't so "mind-blowing" now and possibly may even be considered easy?

jon.