SOLUTION: Find the standard equation of a parabola with vertex (0,5) and containing the point (1 ,-1). Show your work step by step and explain your answer as if you were showing another stud

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the standard equation of a parabola with vertex (0,5) and containing the point (1 ,-1). Show your work step by step and explain your answer as if you were showing another stud      Log On


   



Question 934745: Find the standard equation of a parabola with vertex (0,5) and containing the point (1 ,-1). Show your work step by step and explain your answer as if you were showing another student how to complete this problem.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The general form of the parabola is:
+y+=+a%2Ax%5E2+%2B+b%2Ax+%2B+c+
You are given the points:
( 0, 5 ) and
( 1, -1 )
-------------
( 0, 5 )
By substitution:
+5+=+a%2A0%5E2+%2B+b%2A0+%2B+c+
+c+=+5+
and
( 1, -1 )
+-1+=+a%2A1%5E2+%2B+b%2A1+%2B+c+
+-1+=+a+%2B+b+%2B+c+
since +c+=+5+,
+a+%2B+b+=+-6+
---------------
The x co-ordinate of the vertex point,
( 0,5 ) is defined as:
+x%5Bv%5D+=+-b%2F%282a%29+
So, you can say:
+0+=+-b%2F%282a%29+
+b+=+0+
-------------
So far you have:
+y+=+a%2Ax%5E2+%2B+0%2Ax+%2B+5+
Now go back to:
+a+%2B+b+=+-6+
+b+=+0+
+a+=+-6+
-------------
Now you have:
+y+=+-6x%5E2+%2B+5+
-------------------
check:
Does it go through ( 0,5 )?
+5+=+-6%2A0%5E2+%2B+5+
+5+=+5+
OK
Does it go through ( 1, -1 )?
+-1+=+-6%2A1%5E2+%2B+5+
+-1+=+-6+%2B+5+
+-1+=+-1+
OK
Here's the plot:
+graph%28+400%2C+400%2C+-3%2C+3%2C+-7%2C+7%2C+-6x%5E2+%2B+5+%29+