SOLUTION: ((x-4)^2)/4 + ((y+5)^2)/25 =1 what are the minor end points

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: ((x-4)^2)/4 + ((y+5)^2)/25 =1 what are the minor end points       Log On


   



Question 931413: ((x-4)^2)/4 + ((y+5)^2)/25 =1 what are the minor end points
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
((x-4)^2)/4 + ((y+5)^2)/25 =1 what are the minor end points
%28x-4%29%5E2%2F4%2B%28y%2B5%29%5E2%2F25=1
This is an equation of an ellipse with vertical major axis.
Its standard form:%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1,a>b, (h,k)=coordinates of center
For given problem:
center:(4,-5)
b^2=4
b=2
minor end points:(4±b,-5)=(4±2,-5)=(2,-5) and (6,-5)