SOLUTION: what is the foci of 16x^2+ 4y^2=100

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Question 916523: what is the foci of 16x^2+ 4y^2=100
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2F%28100%2F16%29+%2B+y%5E2%2F%28100%2F4%29+=+1
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center
and ±sqrt%28a%5E2-b%5E2%29are the foci distances from center: a > b
x%5E2%2F%2850%2F4%29+%2B+y%5E2%2F%28100%2F4%29+=+1 C (0,0)
sqrt%28100%2F4+-+50%2F4%29 = sqrt%2850%2F4%29 = 5√2/2
Foci: P( 0, 2.5√2) and P(0, -2.5√2)