SOLUTION: *NOTE that if there is a ! before a letter, that letter is a subscript. Since there is many subscripts, I will put another ! to mark the end of the subscript. Show that, if S!n! i

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: *NOTE that if there is a ! before a letter, that letter is a subscript. Since there is many subscripts, I will put another ! to mark the end of the subscript. Show that, if S!n! i      Log On


   



Question 912970: *NOTE that if there is a ! before a letter, that letter is a subscript. Since there is many subscripts, I will put another ! to mark the end of the subscript.
Show that, if S!n! is the length of one side of a regular polygon inscribed in a circle of radius, r, then the length of one side of a regular polygon with twice as many sides inscribed in the same circle is given by the formula: S%212n%21%5E2+=+2r%5E2+-+rsqrt%28+4r%5E2+-+s%21n%21%5E2+%29

Found 2 solutions by richard1234, richwmiller:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
You may use brackets to denote subscripts on this site, for example:
s[1] +s%5B1%5D+
a[2k] a%5B2k%5D+

Or if you know TeX/LaTeX, the underscore (_) is more standard:

s_1
a_{2k} (note: curly braces required for multi-char superscripts)

Back to your original question, here's a hint: draw a regular n-gon and a regular 2n-gon inside the same circle so that the vertices of the n-gon coincide with n of the vertices of the 2n-gon. You should obtain some isosceles triangles with sides , and . Do some angle chasing and perhaps apply the law of sines or law of cosines.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
! has other meaning
Use [n] for subscripts
s[n]^2
Is this what you mean?
s%5Bn%5D%5E2+=+2%2Ar%5E2+-+r%2Asqrt%28+4r%5E2+-+s%5Bn%5D%5E2+%29