SOLUTION: Find the equation of the tangent to the parabola y^2=12x at the point (2, 5)

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Question 907012: Find the equation of the tangent to the parabola y^2=12x at the point (2, 5)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the tangent to the parabola y^2=12x at the point (2, 5)
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y^2=12x
2ydy = 12dx
dy/dx = 6/y
y'(5) = 6/5
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y-5 = (6/5)*(x-2) is the tangent at (2,5)