SOLUTION: what is the vertex form of 1/2(y+4)=(x-7)^2? i know that the standard form is y=2x^2-28x+94(but im not sure. Is it correct?) what are the steps to get the standard and vertex for

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: what is the vertex form of 1/2(y+4)=(x-7)^2? i know that the standard form is y=2x^2-28x+94(but im not sure. Is it correct?) what are the steps to get the standard and vertex for      Log On


   

Question 902966: what is the vertex form of 1/2(y+4)=(x-7)^2?
i know that the standard form is y=2x^2-28x+94(but im not sure. Is it correct?)
what are the steps to get the standard and vertex form?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Vertex form: y=%28x-h%29%5E2%2Bk
%281%2F2%29%28y%2B4%29=%28x-7%29%5E2
y%2B4=2%28x-7%29%5E2
highlight%28y=%28x-7%29%5E2-4%29
.
.
.
Standard form : y=ax%5E2%2Bbx%2Bc
y%2B4=2%28x-7%29%5E2
y%2B4=2%28x%5E2-14x%2B49%29
y%2B4=2x%5E2-28x%2B98
highlight%28y=2x%5E2-28x%2B94%29
Yes, you're correct.