SOLUTION: Please help me put this equation into standard form: 9x^2+25y^2-54x-100y-44=0. It is a conic section. I tried and got 9(x-3)^2+(y-2)^2/7=1. I put in on Webassign.com and it said th

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please help me put this equation into standard form: 9x^2+25y^2-54x-100y-44=0. It is a conic section. I tried and got 9(x-3)^2+(y-2)^2/7=1. I put in on Webassign.com and it said th      Log On


   

Question 893971: Please help me put this equation into standard form: 9x^2+25y^2-54x-100y-44=0. It is a conic section. I tried and got 9(x-3)^2+(y-2)^2/7=1. I put in on Webassign.com and it said that it was wrong.Please help. Thanks
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
What you found (not yet knowing if it is an equivalent to your given equation) is NOT standard form. The term with the x should be written with a denominator. You know how to make that adjustment?

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Please help me put this equation into standard form: 9x^2+25y^2-54x-100y-44=0. It is a conic section. I tried and got 9(x-3)^2+(y-2)^2/7=1. I put in on Webassign.com and it said that it was wrong.Please help. Thanks 


After COMPLETING THE SQUARE, and setting the equation equal to 1, we get:

Standard form: 

You can do the check!! 



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