SOLUTION: Can you help solve this system? y=3^(2x+1) y=9^(4-2x) I know 9=3^2, so y=(3^2)^(4-2x) Thank you.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Can you help solve this system? y=3^(2x+1) y=9^(4-2x) I know 9=3^2, so y=(3^2)^(4-2x) Thank you.      Log On


   

Question 892459: Can you help solve this system?
y=3^(2x+1)
y=9^(4-2x)
I know 9=3^2, so y=(3^2)^(4-2x)
Thank you.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y=3^(2x+1)
y=9^(4-2x)
I know 9=3^2, so y=(3^2)^(4-2x) , so y = 3^(8-4x)
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Therefore::
3^(2x+1) = 3^(8-4x)
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Then::
2x+1 = 8-4x
6x = 7
x = 7/6
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Cheers,
Stan H.