Question 879144: What is the equation of a hyperbola with foci of (3,2), (3,-2) and an asymptote at y=2(x-3)
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! foci: (3,2), (3,-2) C(3,0) 
Opens Up and down along x = 3
Standard Form of an Equation of an Hyperbola opening up and down is:
 with C(h,k) and vertices 'b' units up and down from center,
Foci  units units up and down from center, along x = h
& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a
asymptote at y=2(x-3), m = ± b/a = 2, b = 2a
foci: = 2 , a^2 = 5/2
and b^2 = 4a^2 = 10
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