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Question 877450: find radius of curvature of
16y^2=4x^4-x^6
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! find radius of curvature of
16y^2=4x^4-x^6
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Find dy/dx and d^2y/d^2x (y' and y")
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16y^2=4x^4-x^6
32ydy = 16x^3dx - 6x^5dx
y' = (8x^3 - 3x^5)/16y
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16ydy = 8x^3dx - 3x^5dx
16d^2y = 24x^2d^2x - 15x^4d^2x
y" = (24x^2 - 15x^4)/16
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Curv = (1 + y"^2)^(3/2)/y"
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Pick a point and sub the values.
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