SOLUTION: Find the x and y intercepts of the parabola. y = {{{-3(x + 4)^2 + 27}}} x:___,___ y:___,___

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the x and y intercepts of the parabola. y = {{{-3(x + 4)^2 + 27}}} x:___,___ y:___,___      Log On


   



Question 876475: Find the x and y intercepts of the parabola.
y = -3%28x+%2B+4%29%5E2+%2B+27
x:___,___
y:___,___

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the x and y intercepts of the parabola.
y = -3%28x+%2B+4%29%5E2+%2B+27
***
y-intercept:
set x=0
y=-3*4^2+27=-48+27=-21
...
x-intercept:
set y=0
-3(x+4)^2+27=0
(x+4)^2=-27/-3=9
(x+4)^2=9
take sqrt of both sides:
x+4=±3
x=-4±3
x=-7, -1
...
y-intercept: (0,-21)
x-intercepts:(-7,0), (-1,0)