SOLUTION: How do i find two extra points for the parabola m^2-5m-14=0. one point found by explaining the symmetry

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How do i find two extra points for the parabola m^2-5m-14=0. one point found by explaining the symmetry      Log On


   

Question 876258: How do i find two extra points for the parabola m^2-5m-14=0. one point found by explaining the symmetry
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The parabola would be the function y=m%5E2-5m-14. You could look at y for m at the midpoint of the zeros and this would be the vertex. You can let m=0 and find the intercept on the y-axis.