Question 875886: Given the ellipse;
2x^2+6y^2+32x-48y+212=0
Find the center, the major axis, the minor axis, and the distance from the center to the foci. Answer by ewatrrr(24785) (Show Source):
Hi
Completing the Square: Need to Know b/2a and -(b/2a)^2
2(x+8)^2 - 128 + 6(y-4)^2 - 96 + 212 = 0
2(x+8)^2 + 6(y-4)^2 =12
(x+8)^2/6 + (y-4)^2/2 =1
center, (-8,4)
the major axis: y = 4
the minor axis: x = -8
distance from the center to the foci: c = sqrt(8) = 2√2
Need to Know...............................................................
Standard Form of an Equation of a Circle is
Standard Form of an Equation of an Ellipse is
Standard Form of an Equation of an Hyperbola opening up and down is:
Standard Form of an Equation of an Hyperbola opening right and left is:
the vertex form of a Parabola opening up(a>0) or down(a<0),
the vertex form of a Parabola opening right(a>0) or left(a<0),
