SOLUTION: 16*x^2-y^2+64*x-2*y+67=0 standard form
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Question 875199
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16*x^2-y^2+64*x-2*y+67=0
standard form
Answer by
ewatrrr(24785)
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16(x +2)^2 - 64 -(y+1)^2 -1 + 67 = 0
(y+1)^2 - 16(x +2)^2 = 2
