SOLUTION: Solve the system: (x+3)^2+(y+2)^2=17 x+y=-2 Enter your solutions as an ordered pair. Write "none" if there are no solutions.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Solve the system: (x+3)^2+(y+2)^2=17 x+y=-2 Enter your solutions as an ordered pair. Write "none" if there are no solutions.      Log On


   

Question 874019: Solve the system:
(x+3)^2+(y+2)^2=17
x+y=-2
Enter your solutions as an ordered pair. Write "none" if there are no solutions.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

x+y=-2  0r y =-x-2

(x+3)^2+(y+2)^2=17

(x+3)^2+(-x)^2=17

2x^2 + 6x - 8 = 0

 x^2 + 3x - 4 = 0

 (x+4)(x-1) = 0, x = -4,1

(-4, 2) and (1, -3) are the solutions for this System