SOLUTION: Write an equation in standard form for the hyperbola with center (0,0) , vertex (0,6) , and focus (0,8). *I tried actually graphing it but it was no use. I also tried b squared

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write an equation in standard form for the hyperbola with center (0,0) , vertex (0,6) , and focus (0,8). *I tried actually graphing it but it was no use. I also tried b squared       Log On


   



Question 870918: Write an equation in standard form for the hyperbola with center (0,0) , vertex (0,6) , and focus (0,8).
*I tried actually graphing it but it was no use. I also tried b squared minus 4 multiplied by a and c.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation in standard form for the hyperbola with center (0,0) , vertex (0,6) , and focus (0,8).
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Given hyperbola has a vertical transverse axis with center at (0,0)
Its standard form of equation: y%5E2%2Fa%5E2-x%5E2%2Fb%5E2=1
a=6
a^2=36
c=8
c^2=64
c^2=a^2+b^2
b^2=c^2-a^2=64-36=28
equation: y%5E2%2F36-x%5E2%2F28=1