Question 863333: Find the equations of the following parabolas:
1.vertex (0,-2)
opens right
passes through (3/2,-1)
2.vertex (0,-1)
opens down
passes through (1,-2)
3.vertex (-3,-1)
opens up
passes through (3,-10/9)
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
1) x = a(y+2)^2 , passes through (3/2,-1), 3/2 = a ,
2) y = ax^2 - 1 , passes through (1,-2), -2 = a - 1, a = -1, 
3) y = a(x+3)^2 - 1, passes through (3,-10/9), -10/9 = 36a - 1, a = -1/4
|
|
|
