SOLUTION: How can I write the equation of an ellipse with the vertex (0,7) and focus (0,5)

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Question 859382: How can I write the equation of an ellipse with the vertex (0,7) and focus (0,5)

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
A parabola has one focus and one vertex.
Knowing the location of focus and vertex, we can write the equation of a parabola.
An ellipse has two foci and two vertices.
As the problem is stated,
with a vertex and a focus on the y-axis,
we know that the major axis lies on the y-axis,
and that means that the center lies on the y-axis,
but we do not know the exact location of the center,
so there is not enough information to write the equation.
There are many possible ellipses with a vertex at (0,7) and a focus at (0,5).

If the ellipse were centered at (0,0), the origin,
a vertex at (0,7) and a focus at (0,5) would give you enough information.
In that case, the semi-major axis distance would be a=7 ;
the focal distance would be c=5 ,
and we would know that the major axis lies on the y-axis.
An ellipse centered at the origin with a major axis along the y-axis as the equation
x%5E2%2Fb%5E2%2By%5E2%2Fa%5E2=1 .
We would need to find b%5E2
We could calculate the semi-minor axis, b ,
from the relation a%5E2=b%5E2%2Bc%5E2 .
In the case of the ellipse centered at (0,0), with a vertex at (0,7) and a focus at (0,5),
7%5E2=b%5E2%2B5%5E2
49=b%5E2%2B25
49-25=b%5E2
b%5E2=24 .
The equation of such an ellipse would be
x%5E2%2F24%2By%5E2%2F49=1 .

If the center is not specified, we cannot write the equation.
With a vertex at (0,7) and a focus at (0,5),
we know that the major axis and the center are along the y-axis,
but we do not know the y-coordinate of the center,
With a center at (0,k), with k%3C5 ,
the lengths of the semi-major axis and the focal distance would be
a=7-k and c=5-k .
Then we would have
b%5E2=%287-k%29%5E2-%285-k%29%5E2
b%5E2=49-14k%2Bk%5E2-%2825-10k%2Bk%5E2%29
b%5E2=49-14k%2Bk%5E2-25%2B10k-k%5E2%29
b%5E2=24-4k%29
and the equation would be
x%5E2%2F%2824-4k%29%2B%28y-k%29%5E2%2F%287-k%29%5E2=1
For example, with the center at (0,2),
the equation would be
x%5E2%2F16%2B%28y-2%29%5E2%2F25=1