SOLUTION: x^2-4x+4y-8=0 standard form

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Question 859201: x^2-4x+4y-8=0 standard form
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

x^2-4x+4y-8=0

(x-2)^2 - 4 +4y - 8 = 0

     4y = -(x-2)^2 +12

      y = -.25(x-2)^2  + 3