SOLUTION: X^2+Y^2-6X+4Y+9=0

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Question 857326: X^2+Y^2-6X+4Y+9=0
Found 2 solutions by ewatrrr, richwmiller:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Please do NOT caps when posting.  So difficult to read.

 x^2 - 6x + y^2 + 4y + 9 = 0

(x-3)^2 +highlight_green%28-9%29 + (y+2)^2 +highlight_green%28-4%29+9 = 0

%28x-3%29%5E2+%2B+%28y%2B2%29%5E2+=+2%5E2+ Circle:  C(3,-2),   r = 2

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
circle
center | (3, -2)
radius | 2
diameter | 4
area | 4 pi=12.5664
perimeter | 4 pi=12.5664
curvature | 1/2
(X-3)^2+(Y+2)^2=4