SOLUTION: Can you please hep me solve this question: Find the equation of the circle with its center in the 3rd quadrant that is tangent to the lines, x=2,x=-6, and y=0
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-> SOLUTION: Can you please hep me solve this question: Find the equation of the circle with its center in the 3rd quadrant that is tangent to the lines, x=2,x=-6, and y=0
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Question 856694: Can you please hep me solve this question: Find the equation of the circle with its center in the 3rd quadrant that is tangent to the lines, x=2,x=-6, and y=0 Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Tangent to x=2 and x=-6 means the center sits on the average or and the radius equal to
Since it's tangent to y=0, the center sits at
So the center is (-2,-4) and the radius is 4.
The general equation for a circle centered at (h,k) with a radius R is :
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