SOLUTION: put into standard form 9x^2-16y^2+54x+160y-320=0

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Question 847862: put into standard form 9x^2-16y^2+54x+160y-320=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
put into standard form
9x^2-16y^2+54x+160y-320=0
9x^2+54x-16y^2+160y-320=0
complete the square:
9(x^2+6x+9)-16(y^2-10y+25)=320+81-400
9(x+3)^2-16(y-5)^2=1
%28x%2B3%29%5E2%2F%281%2F9%29-%28y-5%29%5E2%2F%281%2F16%29=1
This is an equation of a hyperbola with vertical transverse axis.
Its standard form: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center