SOLUTION: Write the equation in vertex form for the parabola with focus (0, 6) and directrix y= -10

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Question 845222: Write the equation in vertex form for the parabola with focus (0,
6) and directrix y= -10

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)
With Directrix y = -(k+p)
focus (0,6) and directrix y= -10, p = %286-%28-10%29%29%2F2+=+8 4p = 32
y = (1/32)x^2 -2