SOLUTION: For the parabola 2x^2-4y + 6x + 1 = 0, (a) find the coordinates of the vertex; (b) find the coordinates of the focus.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: For the parabola 2x^2-4y + 6x + 1 = 0, (a) find the coordinates of the vertex; (b) find the coordinates of the focus.      Log On


   

Question 840547: For the parabola
2x^2-4y + 6x + 1 = 0,
(a) find the coordinates of the vertex;
(b) find the coordinates of the focus.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

2x^2-4y + 6x + 1 = 0

4y= 2(x + 3/2)^2 -9/2 + 1    |Completing Square

 4y= 2(x + 3/2)^2 -7/2

 y+=+%281%2F2%29%28x+%2B+3%2F2%29%5E2+-7%2F8   V(-1.5,-7/8)

4p = 2,  p = 1/2   F(-1.5,-3/8)