SOLUTION: The equation is y^2=-13x It asks the find the foci and directrix and that axis is it on? Thank you for your help!!

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Question 838340: The equation is y^2=-13x
It asks the find the foci and directrix and that axis is it on?
Thank you for your help!!

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
BY DEFINITION
y^2=-13x Or x+=%28-1%2F13%29y%5E2 is a Parabola opening left along the x-axis
See last Standard form Below
Vertex is (0,0), focus is (-13/4,0) and directrix is x = 13/4 (perpendicular line)

See below descriptions of various conics
Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
a and b are the respective vertices distances from center
and ±sqrt%28a%5E2-b%5E2%29are the foci distances from center: a > b
Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 with C(h,k) and vertices 'b' units up and down from center, 2b the length of the transverse axis
Foci sqrt%28a%5E2%2Bb%5E2%29units units up and down from center, along x = h
& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a
Standard Form of an Equation of an Hyperbola opening right and left is:
%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 with C(h,k) and vertices 'a' units right and left of center, 2a the length of the transverse axis
Foci are sqrt%28a%5E2%2Bb%5E2%29 units right and left of center along y = k
& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a

the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)
****the vertex form of a Parabola opening right(a>0) or left(a<0), x=a%28y-k%29%5E2+%2Bh
where(h,k) is the vertex and y = k is the Line of Symmetry
The standard form is %28y+-k%29%5E2+=+4p%28x+-h%29, where the focus is (h +p,k )